Posted by Brittany on Monday, October 26, 2009 at 7:39pm.
This is a limiting reagent problem.
1. Write the equation and balance it.
SrH2 + 2H2O ==> Sr(OH)2 + 2H2 Check me out on that.
2a. Convert 3.78 g SrH2 to moles. moles = grams/molar mass.
2b. Convert 3.5 g H2O to moles.
3a. Using the balanced equation, convert moles SrH2 to moles H2.
3b. Using the balanced equation, convert moles H2O to moles H2.
3c. You have two answers for the same product and one of them MUST be wrong. The correct one, as in ALL limiting reagent problems, is the smaller one. The reactant producing that smaller number is the limiting reagent.
4. The moles from 3c x molar mass = grams produced.
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