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A water slide is constructed so that swimmers, starting from rest at the top of the slide, leave the end of the slide traveling horizontally.

One person hits the water 5.00 m from the end of the slide in a time of 1.000 s after leaving the slide.

Ignoring friction and air resistance, find the height H in the drawing.

P.S. (i tried to use h=ut + 1/2at^2)

  • Physics - ,

    Time, t = 1 s.
    Vertical velocity, u = 0
    H = ut+ (1/2)gt²
    =0*1 -(1/2)(9.8)*1²
    =-4.9 m

    Note: the distance 5 m is not used. When the initial velocity of 5 m/s does not hvae a vertical component, the initial velocity does not affect the outcome.

  • Physics - ,

    Well, your answer is partially right so it's wrong.
    The right answer is:

    H = h1 + h2 = [ut + (1/2)gt^2] + [(1/2)v^2/g] = (0*1 + (1/2)*9.81*1^2) + [(1/2)*(5.00m/1s)^2 / 9.81) = 6.17m

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