Post a New Question

physics

posted by on .

A helicopter is rising at 4.7 m/s when a bag is dropped from it. (Assume that the positive direction is upward.)
(a) After 2.0 s, what is the bag's velocity?
(b) How far has the bag fallen?
(c) How far below the helicopter is the bag?

  • physics - ,

    v(2)=vo*2-9.8(2^2)
    see if you can do the rest.

  • physics - ,

    i still cant do it

  • physics - ,

    b) d(2)=Vo*2-1/2 g (4)
    oops, I did a error in a)
    v(2)=vo -9.8*2 and vo is 4.7
    c) Ok, on how far, it fell b), but the helo went up
    farbelow= 4.7*2+answerinb)

  • physics - ,

    okay i got the answer to b.
    now is a v(2)= vo+(9.8)(2)
    or
    v(2)= vo -(9.8)(2)?

  • physics - ,

    9.8 is a negative quantity, if up is +

  • physics - ,

    so the answer to a should be -14.9 m/s
    and c should be -.08?

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question