Posted by Tay on .
A helicopter is rising at 4.7 m/s when a bag is dropped from it. (Assume that the positive direction is upward.)
(a) After 2.0 s, what is the bag's velocity?
(b) How far has the bag fallen?
(c) How far below the helicopter is the bag?

physics 
bobpursley,
v(2)=vo*29.8(2^2)
see if you can do the rest. 
physics 
Tay,
i still cant do it

physics 
bobpursley,
b) d(2)=Vo*21/2 g (4)
oops, I did a error in a)
v(2)=vo 9.8*2 and vo is 4.7
c) Ok, on how far, it fell b), but the helo went up
farbelow= 4.7*2+answerinb) 
physics 
Tay,
okay i got the answer to b.
now is a v(2)= vo+(9.8)(2)
or
v(2)= vo (9.8)(2)? 
physics 
bobpursley,
9.8 is a negative quantity, if up is +

physics 
Tay,
so the answer to a should be 14.9 m/s
and c should be .08?