physics
posted by Tay on .
A helicopter is rising at 4.7 m/s when a bag is dropped from it. (Assume that the positive direction is upward.)
(a) After 2.0 s, what is the bag's velocity?
(b) How far has the bag fallen?
(c) How far below the helicopter is the bag?

v(2)=vo*29.8(2^2)
see if you can do the rest. 
i still cant do it

b) d(2)=Vo*21/2 g (4)
oops, I did a error in a)
v(2)=vo 9.8*2 and vo is 4.7
c) Ok, on how far, it fell b), but the helo went up
farbelow= 4.7*2+answerinb) 
okay i got the answer to b.
now is a v(2)= vo+(9.8)(2)
or
v(2)= vo (9.8)(2)? 
9.8 is a negative quantity, if up is +

so the answer to a should be 14.9 m/s
and c should be .08?