Starting from rest a car undergoes a constant acceleration of 6 m/s2. How far will the car travel in the first second?
distance=vo*t+1/2 a t^2
t=1, solve for distance.
To find the distance traveled by the car in the first second, you can use the equation of motion:
d = v₀t + (1/2)at²
Where:
d = distance traveled
v₀ = initial velocity (0 m/s since the car starts from rest)
t = time (1 second)
a = acceleration (6 m/s²)
Plug in the values:
d = 0(1) + (1/2)(6)(1²)
d = 0 + (1/2)(6)(1)
d = 0 + (1/2)(6)
d = 0 + 3
d = 3 meters
Therefore, the car will travel 3 meters in the first second.
To calculate the distance traveled by the car in the first second, we can use the equation:
distance = initial velocity * time + (1/2) * acceleration * time^2
Since the car starts from rest, the initial velocity is 0 m/s. The acceleration is given as 6 m/s^2, and the time is 1 second.
Plugging in these values into the equation, we get:
distance = 0 * 1 + (1/2) * 6 * 1^2
distance = 0 + (1/2) * 6 * 1
distance = 0 + (1/2) * 6
distance = 0 + 3
distance = 3 meters
Therefore, the car will travel a distance of 3 meters in the first second.