Wednesday

October 1, 2014

October 1, 2014

Posted by **kamilla** on Monday, October 26, 2009 at 5:07pm.

in 1995, the profit is $280,000

in 1996, the profit is $240,000

in 1997, the profit is $320,000

in 1998, the profit is $310,000

this information is in a chart but charts don't work here so anyways

[it looks something like this:

Year: 1994 1995

Profit: $250,000 $280,000

etc]

so I have to make a scatter plot of the data, which is pretty easy and answer a few questions.. here are the questions that I didn't get:

1. Write a linear model for the amount of profit.

2. Write a linear model to estimate the profit in 2002.

please show/explain how to do these. thnk u

- scatter plots -
**jim**, Monday, October 26, 2009 at 6:49pmOK, so you've plotted your points.

The linear model assumption is that a straight line will go through them. It won't, of course, because they're not perfectly in a line, but the idea is to create a line that comes as close as possible to them, usually with the idea of predicting future numbers from it.

Having plotted your points, you can see that a straight line directly between the first point and the last is not a fit, but it is something like a fit. 1996 messes it up, but the other years aren't too far off. That, then, is one possible linear model. There are others, but this one is simple, so let's follow it for a minute.

We are essentially creating a standard straight line y = mx + c (or Profit = m * Year + c in this case) from the points (1994, 250000) and (1998, 310000). Or, what might make a little more sense, depending, subtract 1994 from the year before starting, so that you're plotting (0, 250000) through (4, 310000). Any of these would be a linear model. Wikipedia has more than you'll ever want to know about this on its Linear_regression page.

Anyway, as one possible approach, let's model (0, 250000) through (4, 310000).

We want y=mx+c

y = (60000/4)x + 250000

Translating it into your graph, we get:

P = 15000(Y-1994) + 250000

which gves us, as we expect, 250000 in 1994 and 310000 in 1998. You can calculate the predicted P for the points inbetween to see that it is sane for the other years, and you should see that those numbers are where the straight line would pass through on your graph.

This is not the best fit line for this graph, and in general, joining up the start and end points probably won't be the best fit, but it's a first estimate, and I figure if your course required one of the specific methods for linear regression, they'd have said so.

Now, for number 2, I think the question must intend: "Use your linear model to

estimate the profit in 2002."

So we have, in Y = 2002,

P = 15000(Y-1994) + 250000

P = 15000(2002-1994) + 250000

P = 120000 + 250000 = 370000.

I'm conscious, writing this, that it's a very simplistic answer. If you need more depth - and boy, there's a lot of material on linear regression! - do ask again.

**Answer this Question**

**Related Questions**

maths - in 1994, the profit is $250,000 in 1995, the profit is $280,000 in 1996...

are these correct - b. Calculate the profit or loss on 12,000 bags and on 25,000...

finite!!! - A manufacturing company wants to maximize profits on products A,B, ...

Statistics - Car P(Sale) % Sold Per Sale/ Profit Per Sale VW Golf 10% 15% $1,...

Microeconomics - I am trying to calculate profit. If I am given the total ...

college algebra - A magazine company had a profit of $98,000 per year when it ...

college algebra - A magazine company had a profit of $98,000 per year when it ...

maths - in 1992, a software company had a profit of $30,000,000. in 1998, the ...

Finance - Item Total assets $10,000,000 Total equity (all common) 9,000,000 ...

Finance - Item Total assets $10,000,000 Total equity (all common) 9,000,000 ...