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July 22, 2014

July 22, 2014

Posted by **Nikita** on Monday, October 26, 2009 at 2:24pm.

- Physics -
**MathMate**, Monday, October 26, 2009 at 2:41pmDid you get the previous problem?

http://www.jiskha.com/display.cgi?id=1256570375

If you have questions, don't be shy to make a follow-up.

Basically, the centripetal acceleration has to offset gravity, 9.8 m/s².

Since the centripetal acceleration is given by v²/r, so we equate the two quantities to get

v²/r = 9.8

v=sqrt(9.8*r) m/s

= sqrt(9.8*13.3) m/s

= 11.4 m/s.

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