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algebra (check plz)

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write an equation in slope-intercept form of the line that passes through the given points.
a. (-6,1), (3,-7)
b. (-2/3,4), (6, -1/3)

write an equation in point-slope form of the line that passes through the given poitns.
c. (-2,5), (4,-3)
d. (1/2,-1), (-2/3,6)
_______________________

this is what I got.. is it correct?

a. y = -8x/3 + 1

b. y = -13x/20 + 107/30

c. y + 3 = (-4/3)(x + 2)

d. y + 1 = -6x + 3

and if not, can you please correct them? (: thanks

  • algebra (check plz) - ,

    a) your first point does not satisfy your equation, so your equation is incorrect
    slope = (-7-1)/(3+6) = -8/9

    so y = (-8/9)x + b
    sub in (-6,1)
    1 = (-8/9)(-6) + b
    9 = 48 + 9b
    b = -39/9 = -13/3

    so y = (-8/9)x - 13/3

    b) ok

    c) you picked the y-coordinate from one point, and the x-coordinate of the other !!
    Instead : y + 3 = (-4/3)(x - 4)

  • algebra (check plz) - ,

    thanks!! (((:

    what about D.? ):

  • algebra (check plz) - ,

    d) is not wrong, but it's not in its final form; you have a constant on each side.

    Subtract one from each side to get rid of the 1 on the LHS and you'll be finished.

  • algebra (check plz) - ,

    okay (:
    thanks again for your help!

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