Posted by **<3 ** on Monday, October 26, 2009 at 1:49pm.

write an equation in slope-intercept form of the line that passes through the given points.

a. (-6,1), (3,-7)

b. (-2/3,4), (6, -1/3)

write an equation in point-slope form of the line that passes through the given poitns.

c. (-2,5), (4,-3)

d. (1/2,-1), (-2/3,6)

_______________________

this is what I got.. is it correct?

a. y = -8x/3 + 1

b. y = -13x/20 + 107/30

c. y + 3 = (-4/3)(x + 2)

d. y + 1 = -6x + 3

and if not, can you please correct them? (: thanks

- algebra (check plz) -
**Reiny**, Monday, October 26, 2009 at 2:11pm
a) your first point does not satisfy your equation, so your equation is incorrect

slope = (-7-1)/(3+6) = -8/9

so y = (-8/9)x + b

sub in (-6,1)

1 = (-8/9)(-6) + b

9 = 48 + 9b

b = -39/9 = -13/3

so y = (-8/9)x - 13/3

b) ok

c) you picked the y-coordinate from one point, and the x-coordinate of the other !!

Instead : y + 3 = (-4/3)(x - 4)

- algebra (check plz) -
**<3 **, Monday, October 26, 2009 at 3:09pm
thanks!! (((:

what about D.? ):

- algebra (check plz) -
**jim**, Monday, October 26, 2009 at 3:17pm
d) is not wrong, but it's not in its final form; you have a constant on each side.

Subtract one from each side to get rid of the 1 on the LHS and you'll be finished.

- algebra (check plz) -
**<3 **, Monday, October 26, 2009 at 3:40pm
okay (:

thanks again for your help!

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