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posted by RE Monday, October 26, 2009 at 11:51am.
It takes 180 kJ of work to accelerate a car from 21.0 m/s to 27.5 m/s. What is the car's mass? kg?
Initial kinetic energy = (1/2)mv0² Final kinetic energy = (1/2)mv1² Difference E = (1/2)m(v1²-v0²) Solve for m
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