Monday

March 30, 2015

March 30, 2015

Posted by **Anonymous** on Monday, October 26, 2009 at 11:42am.

- math -
**Dr Russ**, Monday, October 26, 2009 at 11:46amSet it up as two equations

AxB=50 ........(1)

and

A/B=2..........(2)

or A=2B

substitute (2) in (1)

2B^2=50

solve for B

then A=2B

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