Posted by **Nikita** on Monday, October 26, 2009 at 11:19am.

A roller coaster ride includes a circular loop with radius R = 11.6 m. What minimum speed must the car have at the top to stay in contact with the tracks?

How would I go around solving this, as in what formula would I need?

- Physics -
**MathMate**, Monday, October 26, 2009 at 11:43am
The centripetal acceleration is given by v²/r m/s².

Acceleration due to gravity is g=9.8 m/s²

If one is to offset the other, they must be equal. at the highest point of the loop.

So set

v²/r = g

to solve for v.

Note: at this speed, the normal force on the track is zero.

## Answer This Question

## Related Questions

- Physics - A roller coaster ride includes a circular loop with radius R = 13.3 m...
- physics - A roller coaster ride includes a circular loop with radius R = 13.1 m...
- physics - A roller coaster has a vertical loop with radius 17.9 m. With what ...
- Physics - A roller coaster works by gravitational energy. The coaster car is ...
- physics - 3.A roller coaster has a vertical loop with radius 27.1 m. With what ...
- Physics - A 775 kg roller coaster car is at the top of a roller coaster car is ...
- Physics - A car is doing a loop-the-loop. The loop has a radius of .4m. Assume ...
- physics - The radius of curvature of a loop-the-loop for a roller coaster is 11....
- Physics - The radius of curvature of a loop-the-loop for a roller coaster is 11....
- Physics - The radius of curvature of a loop-the-loop for a roller coaster is 11....

More Related Questions