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August 29, 2014

August 29, 2014

Posted by **Nikita** on Monday, October 26, 2009 at 4:22am.

2x^3 - 3x^2 + 3x -1 = 0

I just don't know how to do it because there is a coefficient in front of first term.

- Calculus -
**Reiny**, Monday, October 26, 2009 at 8:07amAfter you tried ± 1 and that didn't work, you would now try ± 1/2

sure enough, x = 1/2 works

(2(1/2)^3 - 3(1/2)^2 + 3(1/2) - 1

= 1/4 - 3/4 + 3/2 - 1

= 0

so (2x - 1) is a factor

Now you can do your long division, and get the other factor to be

(x^2 - x + 1)

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