Wednesday

July 30, 2014

July 30, 2014

Posted by **Nikita** on Monday, October 26, 2009 at 4:22am.

2x^3 - 3x^2 + 3x -1 = 0

I just don't know how to do it because there is a coefficient in front of first term.

- Calculus -
**Reiny**, Monday, October 26, 2009 at 8:07amAfter you tried ± 1 and that didn't work, you would now try ± 1/2

sure enough, x = 1/2 works

(2(1/2)^3 - 3(1/2)^2 + 3(1/2) - 1

= 1/4 - 3/4 + 3/2 - 1

= 0

so (2x - 1) is a factor

Now you can do your long division, and get the other factor to be

(x^2 - x + 1)

**Related Questions**

algebra 2 - can someone please explain synthetic division to me? It's just a ...

Calculus - Let f(x)=(2x^3-x^2+2x+1)/(x^2+1). What is the equation of the oblique...

Calculus - Ok so I have to find a vertical asymptote with denominator 3x^3-x-1. ...

lisa - This is a question given to me to answer:How is dividing a polynomial by ...

math - how do i do long division? This web site may help you. http://www....

Algebra - Divide using long division or synthetic division. (21x^3 - 7)/(3x - 1...

Algebra - Divide using long division or synthetic division. (21x^3 - 7)/(3x - 1...

algebra - what is the answer for x squared + 9 divided by -x-4?? a strange ...

Quadratic - This is the question: "Find the values of b and c for which x^2+bx+c...

Quadratic Long Division question? - How do i do this using long division? This ...