Posted by **Nikita** on Monday, October 26, 2009 at 4:22am.

How do you find factors of this with long division?

2x^3 - 3x^2 + 3x -1 = 0

I just don't know how to do it because there is a coefficient in front of first term.

- Calculus -
**Reiny**, Monday, October 26, 2009 at 8:07am
After you tried ± 1 and that didn't work, you would now try ± 1/2

sure enough, x = 1/2 works

(2(1/2)^3 - 3(1/2)^2 + 3(1/2) - 1

= 1/4 - 3/4 + 3/2 - 1

= 0

so (2x - 1) is a factor

Now you can do your long division, and get the other factor to be

(x^2 - x + 1)

## Answer this Question

## Related Questions

- algebra 2 - can someone please explain synthetic division to me? It's just a ...
- Calculus - Let f(x)=(2x^3-x^2+2x+1)/(x^2+1). What is the equation of the oblique...
- Pre-Calc - How do I determine if there are common factors for x^5+3x^3+5x/4X^4+...
- Calculus - Ok so I have to find a vertical asymptote with denominator 3x^3-x-1. ...
- lisa - This is a question given to me to answer:How is dividing a polynomial by ...
- math - how do i do long division? This web site may help you. http://www....
- Algebra - Divide using long division or synthetic division. (21x^3 - 7)/(3x - 1...
- Algebra - Divide using long division or synthetic division. (21x^3 - 7)/(3x - 1...
- algebra - what is the answer for x squared + 9 divided by -x-4?? a strange ...
- Quadratic - This is the question: "Find the values of b and c for which x^2+bx+c...