Homework Help Forum: Trigonometry

Posted by Jasmine on Sunday, October 25, 2009 at 10:24pm.

How do you figure out the exact circular function value of sec(23pie/6)? *I don't know how to get the [pie]symbol on my keyboard

• Trigonometry - Reiny, Monday, October 26, 2009 at 12:03am

  23pi/6 is pi/6 short of two rotations of 4pi so 23pi/6 is coterminal with -pi/6 (23pi/6 = 690º. 690º - 360º = 330 or -30º) sec (23pi/6) = sec (-pi/6) = 1/cos(-pi/6) = 1/cos(pi/6) = 1/(√3/2) = 2/√3 or 2√3/2 after rationalizing the denominator

  
  

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