Jiskha Homework Help
SATURDAY
November 21, 2009
SCHOOL SUBJECTS
- Art
- Business
- Computers
- English
- Foreign Languages
- Health
- Home Economics
- Math
- Music
- Physical Education
- Science
- Social Studies
GRADE LEVELS
- Preschool
- Kindergarten
- Elementary School
- 1st Grade
- 2nd Grade
- 3rd Grade
- 4th Grade
- 5th Grade
- 6th Grade
- 7th Grade
- 8th Grade
- High School
- 9th Grade
- 10th Grade
- 11th Grade
- 12th Grade
- College
- Adult Education
Post a New Question | Current Questions | Chat With Live Tutors

Homework Help Forum: Economics/Algebra

Posted by cb on Sunday, October 25, 2009 at 2:07pm.

Can someone help with the following: I know how to get the MC and AC; however I'm not sure on the algabraic part.

Given the following short-run total cost function, answer the following questions.

TC = 3q2 + 5q + 300

a. Find the marginal and average cost functions.

b. Show that AC is at its minimum when q = 10 and that MC = AC at this output.


  • Economics/Algebra - MathMate, Sunday, October 25, 2009 at 3:41pm

    A.
    Given:
    tc(q)= 3q²+5q+300
    The marginal cost is what would cost an extra item (quantity) for a given quantity q. It is obtained by finding the derivative of tc(q) with respect to q:
    marginal cost, mc(q)
    = tc'(q)
    = d(tc(q))/dq
    = 6q+5

    Average cost is the total cost of q items averaged over q, i.e. divided by q.
    average cost, ac(q)
    = tc(q)/q

    B.
    mc(10) = 6*10+5 = 65
    ac(10) = (3*(10)² + 5*(10) + 300 )/10
    = 65

    Thus mc(10) = ac(10)

Answer this Question

First Name:
School Subject:
Answer:

For Further Reading

SEARCH

COMMUNITY
FEATURES
- Live Tutors
- Net Riddle
- Reference
- Search