Posted by Adriana on .
I distributed 3x^2+x10=f(x) to find the zeroes. My book's answer was (3x5)(x+2). When I distributed this to make sure I got the original function, I got 3x^2x10. Is this still an acceptable way to factor it even though the x is negative instead of positive as it should be? I got the answers the book got through this method (5/3 and 2) But I don't see how this can be correct with the x being negative.

Algebra 
MathMate,
Use FOIL
(3x5)(x+2)
=3x*x + 3x*2 5*x 5(2)
=3x² + 6x 5x 10
=3x² + x 10
as in the original expresion, and the answer is correct.