Posted by <3 on Sunday, October 25, 2009 at 12:23pm.
First, from a given line, the slope can be identified if the equation of the line is put into the slope-intercept form as:
y = mx + b
For example,
2x + 3y = 5 can be rearranged to
y = (-2/3)x + 5/3
From which we can identify the slope as (-2/3).
One the slope is defined, if the line is to pass through a given point with coordinates (x1,y1), the equation of the line sought is:
y = m(x-x1) + y1
So if a line parallel to the above line is to pass through (3,2), the equation would be:
y = (-2/3)(x - 3) + 2, or
y = (-2/3)x + 4
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