Posted by Adriana on Saturday, October 24, 2009 at 10:37pm.
I think you mean
1/(2x^3-x)
factoring the denominator
x(2x^2-1)= x(xsqrt2-1)(xsqrt2+1)
(1/2)x(x^2 - 2) = 0
x = 0 or x = ± √2
See how the same question can be interpreted in more than one way if you don't use brackets?
I read it as (1/2)x^3-x
bobpursley read it as 1/(2x^3-x)
or why not 1/(2x^3) - x ?
Related Questions
math - Find the zeroes of the function y=3x^3-3x So I factored that to y=3x(x^2-...
algebra - Find the zeroes of each function. State the multiplicity of multiple ...
Algebra - I distributed 3x^2+x-10=f(x) to find the zeroes. My book's answer ...
Algebra - I'm trying to solve x^3-3x^2-x+3 is less than zero. Except, I'...
Calculus - relative extrema x^4-2x^2+5 so far I know how to find the derivative ...
Add the Polynomials - (9X^3+2X^2-7)+(2X^3-2X+9) IS ANSWER: 11X^3+2X^2-2X+2
Algebra for Reiny/Bob - The way my book has it is (1/2x^3)-x. Sorry for the ...
factor the trinomial by grouping - 15x^3-9x^2-6x Can someone please show me how ...
Algebra - State the possible number of imaginary zeros of g(x)= x^4+3x^3+7x^2-6x...
Algebra - I'm not sure how to factor x^3-4x is greater than/equal to 0 so ...
For Further Reading
