Posted by **Adriana** on Saturday, October 24, 2009 at 10:37pm.

How do you factor 1/2x^3-x so that the zeroes can be found? Thank you-Adriana

- Algebra -
**bobpursley**, Saturday, October 24, 2009 at 11:12pm
I think you mean

1/(2x^3-x)

factoring the denominator

x(2x^2-1)= x(xsqrt2-1)(xsqrt2+1)

- Algebra -
**Reiny**, Saturday, October 24, 2009 at 11:13pm
(1/2)x(x^2 - 2) = 0

x = 0 or x = ± √2

- Adriana - Algebra -
**Reiny**, Saturday, October 24, 2009 at 11:16pm
See how the same question can be interpreted in more than one way if you don't use brackets?

I read it as (1/2)x^3-x

bobpursley read it as 1/(2x^3-x)

or why not 1/(2x^3) - x ?

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