Physics
posted by Rachel on .
Suppose that in the same Atwood setup another string is attached to the bottom of m1 and a constant force f is applied, retarding the upward motion of m1. If m1 = 5.30 kg and m2 = 10.60 kg, what value of f will reduce the acceleration of the system by 50%?
thank you!

m2*gm1*gF=ma/2
where
g(m2m1)=ma
so
g(m2m1)F=g(m2m1)/2
solve for F 
F= {9.8m/s^2 (10.65.30)}/ 2
F= {9.8 (5.3)}/2
F= 51.94/2
F= 25.97
{Significant figures} F = 26N