Friday

August 29, 2014

August 29, 2014

Posted by **Laura** on Saturday, October 24, 2009 at 5:56pm.

my notes say y' = 5x^2sec5xtan5x-2xsec5x

i get y'= sec5x(-2x^-3)+sec5xtan5x(5)(x^-2) when i change it to (sec5x)(x^-2)

or by quotient rule

[ (x^2)(sec5x)(tan5x)(5)-(sec5x)(2x) ] / (x^4)

which is correct?

- // calculus - derivatives -
**bobpursley**, Saturday, October 24, 2009 at 6:04pmyours is correct

**Related Questions**

calculus pleas pleas help, derivates - what is the derivative of x/tan(x) and ...

Calculus (derivatives) - Find the points on the graph of f where the tangent ...

// calculus - trig derivatives - how do i do i do y=cos(radt)+ rad(cost)? ---- f...

Calculus - f(x)=5+(6/x)+(7/x^2), find f'(x). I haven't done fractions without ...

Calculus - Let f(x)= 5x ------- x–2 are we supposed to use the quotient rule? ...

Calculus - find the derivative of f(x)=tanx-4/secx I used the quotient rule and ...

Calculus - How do I use the chain rule to find the derivative of square root(1-x...

Calculus/Derivatives - In addition, can you walk me through how to get the ...

calculus help - Is there any good calculus websites out there that teach every ...

calculus - The length l of a rectangle is decrasing at a rate of 5 cm/sec while ...