Posted by **Laura** on Saturday, October 24, 2009 at 5:56pm.

y = sec(5x) / x^2

my notes say y' = 5x^2sec5xtan5x-2xsec5x

i get y'= sec5x(-2x^-3)+sec5xtan5x(5)(x^-2) when i change it to (sec5x)(x^-2)

or by quotient rule

[ (x^2)(sec5x)(tan5x)(5)-(sec5x)(2x) ] / (x^4)

which is correct?

- // calculus - derivatives -
**bobpursley**, Saturday, October 24, 2009 at 6:04pm
yours is correct

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