Posted by mousey on Saturday, October 24, 2009 at 5:12pm.
I get
1/(x-3)(x+3) = A/(x-3) + B/(x+3)
1 = (x+3)A + (x-3)B
1 = x(A+B) + 3A -3B
-> A + B = 0 -> A = -B
-> 3A - 3B = 1 -> A = 1/6; B = -1/6
= (1/6)(x-3) - (1/6)/(x+3)
thanks so it is the same thank god for that
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