Friday

January 30, 2015

January 30, 2015

Posted by **mousey** on Saturday, October 24, 2009 at 5:12pm.

is 1/6(x-3)-1/6(x+3) correct or have i gone wrong somewhere

- math -
**jim**, Saturday, October 24, 2009 at 7:08pmI get

1/(x-3)(x+3) = A/(x-3) + B/(x+3)

1 = (x+3)A + (x-3)B

1 = x(A+B) + 3A -3B

-> A + B = 0 -> A = -B

-> 3A - 3B = 1 -> A = 1/6; B = -1/6

= (1/6)(x-3) - (1/6)/(x+3)

- math -
**mousey**, Sunday, October 25, 2009 at 5:45amthanks so it is the same thank god for that

**Answer this Question**

**Related Questions**

Calc easy - Having trouble getting the correct solution. The integral of “x ...

Math- Partial Fractions - Decompose the following into partial fractions after ...

CALC 2 - Partial Functions!! - How do I solve Integral of 7/(16-x^2) I know I ...

calculus - Decompose 58-x/x^2-6x-16 into partial fractions.

Calculus - Partial Fractions - What is the integral of 7e^(7t) Divided By e^14t+...

Binomial - Help me on this one :( Express y= (7-3x-x^2)/[((1-x)^2)(2+x)] in ...

Calculus - Find the integral of x/ (x^4+x^2+1) from 2 to 3. I was going to ...

Pre-Algebra [repost for Reiny] - In my last post for #1, I asked my teacher and ...

Algebra - Is this right? Decompose into partial fractions. (2x^2-24x+35)/(x^2+2x...

calculus - how do you evauste the intergral intergral (2x^4-2x^3+6x^2-5x+1)/(x^3...