Posted by Muffy on Saturday, October 24, 2009 at 5:00pm.
Solve: (x+5/x)+(6/x4)=(7/x^24x)
I multiplied the entire function by x and x4 and after doing that I got down to the quadratic equation
x^2+7x13=0
I did the quadratic and got
x=1.525 and 8.525
I feel like I made a mistake because when I plug in both of those answers for x separately, it never works out. Not sure if I made an error in calculating or in plugging in, or if there is no solution.
Thanks.

Pre Calc still confused  bobpursley, Saturday, October 24, 2009 at 6:17pm
(x+5)(x4)+ 6x=7
x^2+x20+6x=7
x^2+7x13=0
x= (7 +sqrt (49+52))/2=(7+10.04)/2
x=17/2, 3/2 your answers 
Pre Calc one more thing  Muffy, Saturday, October 24, 2009 at 6:28pm
When I plug them in they don't work. am I plugging them in wrong or is it no solution?

Pre Calc still confused  jim, Saturday, October 24, 2009 at 6:32pm
Are the brackets right?
I've tried
(x+5/x)+(6/x4)=(7/x^24x),
and
(x+5)/x + 6/(x4)=7/(x^24x)
and a couple of other permutations without achieving enlightenment. 
Pre Calc still confused  jim, Saturday, October 24, 2009 at 6:53pm
OK. If it's
(x+5)/x + 6/(x4)=7/(x^24x)
then I agree with bobpursley's answer
but the numerical answers aren't exactly 17/2 and 3/2; they're
(7+sqrt(101))/2. If you plug 3/2 in, it'll be close but not zero.
6.5/1.5 + 6/(1.54)+7/(1.5^24*1.5) 
Pre Calc still confused  jim, Saturday, October 24, 2009 at 6:55pm
Oops. Left off the last equals:
6.5/1.5 + 6/(1.54)+7/(1.5^24*1.5) = 0.066666...