Saturday

December 20, 2014

December 20, 2014

Posted by **Muffy** on Saturday, October 24, 2009 at 3:51pm.

I multiplied the entire function by x and x-4 and after doing that I got down to the quadratic equation

x^2+7x-13=0

I did the quadratic and got

x=1.525 and -8.525

I feel like I made a mistake because when I plug in both of those answers for x separately, it never works out. Not sure if I made an error in calculating or in plugging in, or if there is no solution.

Thanks.

- pre calc -
**Thomas**, Saturday, October 24, 2009 at 4:45pmyour answer is wrong.... redo the problem and move 1.5 and make it 5.125

- pre calc -
**Muffy**, Saturday, October 24, 2009 at 4:48pmI'm not quite sure what you mean. Can you please elaborate

- pre calc -
**jim**, Saturday, October 24, 2009 at 5:26pmNot sure you should go by me, because I took it down wrong the first time, but I got:

x + 11/x - 4 + 7/x^2 + 4x = 0

Gathering and multiplying by x^2:

5x^3 - 4x^2 + 11x + 7 = 0

Does this makes sense to you in the context of your course?

**Answer this Question**

**Related Questions**

Pre Calc still confused - Solve: (x+5/x)+(6/x-4)=(-7/x^2-4x) I multiplied the ...

Pre Calc (For Reiny) - Thanks so much your method worked perfectly! My solution ...

Pre Calc - I am familiar with this type of problem but can't seem to get the ...

Pre-calc - Use the given zero to find the remaining zeros of the function: h(x)=...

algebra II - I'm quite clueless as to how to solve this. I know the quadratic ...

Algebra Problems - Please check my answers. Find the coordinates of the vertex ...

Algebra - Please check my answers. Find the coordinates of the vertex for the ...

Algebra - Please check my answers. Find the coordinates of the vertex for the ...

pre calc - 2x^2+4x-5 Rewrite quadratic function in standard form.

pre calc - use the quadratic formula to solve for x. x^2+2x+5-0