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posted by amelia on Saturday, October 24, 2009 at 1:54pm.
how do you solve 2(2^2x)-5(2^x)+2=0 for x
Let 2^x = y then your equation becomes 2y^2 - 5y + 2 = 0 (2y-1)(y-2) = 0 y = 1/2 or y = 2 then 2^x = 1/2 --- x = -1 or 2^x = 2 --- x = 1
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