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algebra

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how do you solve 2(2^2x)-5(2^x)+2=0 for x

  • algebra - ,

    Let 2^x = y
    then your equation becomes
    2y^2 - 5y + 2 = 0
    (2y-1)(y-2) = 0
    y = 1/2 or y = 2

    then 2^x = 1/2 --- x = -1
    or
    2^x = 2 --- x = 1

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