Posted by amelia on Saturday, October 24, 2009 at 1:54pm.
Let 2^x = y
then your equation becomes
2y^2 - 5y + 2 = 0
(2y-1)(y-2) = 0
y = 1/2 or y = 2
then 2^x = 1/2 --- x = -1
or
2^x = 2 --- x = 1
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