hopefully this helps...
"Ether is the oxide of this base, and alcohol the hydrated oxide; that is, chemically regarded, the only difference between ether and alcohol is, that the latter contains one equivalent of water"
albumen . conservation-us . org/ library/ monographs/ sunbeam/ chap08. html
I'm not quite sure I quite understand. ^^;;.
I've done some googling and found that as alcohols get bigger, they lose their solubility in water because they are too big. Although, I know ether can dissolve the alcohols through hydrogen bonds (I think). I don't see why ether is more effective.
Remember that like dissolves like. It is true that the alcohol contains OH which is like water; however, think of the alcohol as ROH. As long as R (the hydrocarbon part of the alcohol) is small, it will be soluble in water. CH3OH, C2H5OH, C3H7OH (methyl, ethyl, propyl alcohols) are quite soluble in water because the R part is relatively small. However, with benzyl alcohol, that has the benzyl part for R (C6H5CH2OH). In effect, benzyl alcohol behaves less as an OH and more as the R part; therefore, it is more insoluble in water and more soluble in organic solvents like ether.
I see that makes sense! I didn't see why I didn't think of it haha. I kept thinking like dissolves like for polar/nonpolar which is irrelevant in this case. I wasn't sure if I should use the concept as you said. Thanks!
which is more soluble in water methyl fluoride or hydrogen flouride and why