12th grade Physics
posted by Jane on .
how much tension must a rope withstand if it is used to accelerate a 1200-kg car vertically upward at .80 m/s^2?
Force required to accelerate the car vertically = m * (v^2)
= 1200 * (0.8^2)
= 1200 * 0.64
This force will be equal to the tension on the rope.
these are the answer choices though
tension=mg+ma=m(9.8+.8)= to two decimal places.