Calculus
posted by Anonymous on .
find the acceleration at time t=9s if the position (in cm) of a particle moving along a line is s(t)=6t^37t^29t+2 at time t.

V(t) = dS/dt = 18t^2  14t 9
Acceleration = dV/dt = 36t14
Plug the value of "t" in the above and that's the answer