Posted by **Anonymous** on Saturday, October 24, 2009 at 6:58am.

The surface area of a piece of gold is directly proportional to the square of its weight. By what ratio should the weight be adjusted so as to double the surface area.

- Mathematics -
**bobpursley**, Saturday, October 24, 2009 at 7:08am
surface area= k w^2

w=sqrt (area/k)

double surface area.

w'=w sqrt2

- Mathematics -
**Anonymous**, Saturday, October 24, 2009 at 8:53am
Thanks.I had a similar question in my recent exam. I followed a similar procedure...Made a silly error though at the end,forgot to square root..I ended up with w^2'=2w^2.

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