Posted by Anonymous on Saturday, October 24, 2009 at 6:58am.
The surface area of a piece of gold is directly proportional to the square of its weight. By what ratio should the weight be adjusted so as to double the surface area.

Mathematics  bobpursley, Saturday, October 24, 2009 at 7:08am
surface area= k w^2
w=sqrt (area/k)
double surface area.
w'=w sqrt2

Mathematics  Anonymous, Saturday, October 24, 2009 at 8:53am
Thanks.I had a similar question in my recent exam. I followed a similar procedure...Made a silly error though at the end,forgot to square root..I ended up with w^2'=2w^2.
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