Homework Help: Mathematics

Posted by Anonymous on Saturday, October 24, 2009 at 6:58am.

The surface area of a piece of gold is directly proportional to the square of its weight. By what ratio should the weight be adjusted so as to double the surface area.

Mathematics - bobpursley, Saturday, October 24, 2009 at 7:08am
surface area= k w^2

w=sqrt (area/k)
double surface area.
w'=w sqrt2
Mathematics - Anonymous, Saturday, October 24, 2009 at 8:53am
Thanks.I had a similar question in my recent exam. I followed a similar procedure...Made a silly error though at the end,forgot to square root..I ended up with w^2'=2w^2.

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