Posted by **Z32** on Friday, October 23, 2009 at 5:14pm.

Help me simplify this down some more so I can set it to zero and find my critical points.

f(x) = x^3 (x+2)^6

f'(x) = x^3 * 6(x+2)^5 + 3x^2 * (x+2)^6

## Answer this Question

## Related Questions

- Calculus - Explain the global optimization process for a continuous function ...
- Calculus - How many critical points does the function f(x) = [(x-2)^5][(x+3)^4] ...
- Math - How do you find critical points in a function? For example, find the ...
- Calc - Classify all critical points of the function f(x,y)=x^2-y^2+4x-2y+1. I ...
- calculus - Use a graph of f(x) = 3 e^{-8 x^2} to estimate the x-values of any ...
- Calculus - Sketch the graph of f(x)=x+2/x-4. Find the vertical and horizontal ...
- Calculus - For y=(1/4)x^4-(2/3)x^3+(1/2)x^2-3, find the exact intervals on which...
- AP Calculus - For the function y=4-2x^2+1/6x^4 find the following: Domain x and ...
- calculus - the graph (x^5-15*x^3 +10) is sketched without axes and not to scale...
- Calculus - Can someone help me finish this question... I got most of the ...