Posted by Rachel on .
A 45 kg trunk is pushed 7.8 m at constant speed up a 30° incline by a constant horizontal force. The coefficient of kinetic friction between the trunk and the incline is 0.23.
a)Calculate the work done by the applied horizontal force.
b)Calculate the work done by the weight of the trunk.
c)How much energy was dissipated by the frictional force acting on the trunk?
I found a to be 2773.4 J and b to be -1719.9 J but i cannot get c at all. Im not even sure what equation to use.
c. energyinfriction= frictionforce*distance
= 45gCos30*mu*7.8 Joules