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April 20, 2014

Homework Help: Caluclus

Posted by Z32 on Friday, October 23, 2009 at 12:57am.

[Mean Value Theorem]

f(x)=-3x^3 - 4x^2 - 2x -3 on the closed interval [0,8].

Find the smallest value of c that satisfies the conclusion of the Mean Value Theorem for this function defined on the given interval.

I got 8 - sqrt(5696) / -18 = 3.748436059 but it's not right.

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