Posted by Z32 on Friday, October 23, 2009 at 12:57am.
[Mean Value Theorem]
f(x)=3x^3  4x^2  2x 3 on the closed interval [0,8].
Find the smallest value of c that satisfies the conclusion of the Mean Value Theorem for this function defined on the given interval.
I got 8  sqrt(5696) / 18 = 3.748436059 but it's not right.

Caluclus  Z32, Friday, October 23, 2009 at 1:49am
I redid my math and I think I did my calculations wrong. I got 8 + sqrt(8000)/ 18 but it's still wrong.

Caluclus  Z32, Friday, October 23, 2009 at 2:43am
Nevermind, I had an error in my calculations. It was sqrt(8128). I got the answer.
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