Posted by **Z32** on Friday, October 23, 2009 at 12:57am.

[Mean Value Theorem]

f(x)=-3x^3 - 4x^2 - 2x -3 on the closed interval [0,8].

Find the smallest value of c that satisfies the conclusion of the Mean Value Theorem for this function defined on the given interval.

I got 8 - sqrt(5696) / -18 = 3.748436059 but it's not right.

- Caluclus -
**Z32**, Friday, October 23, 2009 at 1:49am
I redid my math and I think I did my calculations wrong. I got 8 +- sqrt(8000)/ -18 but it's still wrong.

- Caluclus -
**Z32**, Friday, October 23, 2009 at 2:43am
Nevermind, I had an error in my calculations. It was sqrt(8128). I got the answer.

## Answer this Question

## Related Questions

- Calculus - Verify the hypothesis of the mean value theorem for each function ...
- math - verify that the function satisfies the hypothesis of the mean value ...
- calculus - verify that the function satisfies the hypothesis of the mean value ...
- Math11 - Hello, I dont know how to do this, please help. Thank you. 1).Does the ...
- ap calc - Find the value of c which satisfies Mean Value Theorem for the ...
- math - verify that the function satisfies the hypotheses of the mean values ...
- Calculus - Given f(x) = -1/x, find all c in the interval [-3, -½] that satisfies...
- calculus help - Does the function satisfy the hypotheses of the Mean Value ...
- Calculus Help Please!!! - does the function satisfy the hypotheses of the Mean ...
- Calculus Help Please!!! - Does the function satisfy the hypotheses of the Mean ...

More Related Questions