Bill is standing on a bridge and kicks stones to the water below. If bill kicks a stone with a horizontal velocity of 3.5 m/s, and it lands in the water at a horizontal distance of 5.4m. What is the height of the bridge?
Do I need to find the time first?? If so can I use a rewritten version of Vf = Vi + gt where Vf = 0?
PHYSICS - MathMate, Friday, October 23, 2009 at 7:13am
Time, t = horiz. distance / horiz. velocity
Solve for vertical distance, H using
H = v0t+(1/2)gt²