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Bill is standing on a bridge and kicks stones to the water below. If bill kicks a stone with a horizontal velocity of 3.5 m/s, and it lands in the water at a horizontal distance of 5.4m. What is the height of the bridge?

Do I need to find the time first?? If so can I use a rewritten version of Vf = Vi + gt where Vf = 0?

  • PHYSICS - ,

    Time, t = horiz. distance / horiz. velocity
    Solve for vertical distance, H using
    H = v0t+(1/2)gt²

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