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September 20, 2014

September 20, 2014

Posted by **jane** on Thursday, October 22, 2009 at 6:23pm.

This is the formula I figured out so far.

V(average)=V(jet)-V(cargo

100km/h= d/t - d/t

100= [1400km/x] - [1400/(.25x+x)]

But from here I don't know what to do..

- math(rational functions application) -
**jim**, Thursday, October 22, 2009 at 6:34pmCall the speeds j and c.

j - c = 100 -> j = 100 + c

(100 + c) = 5c / 4 (from the "25% faster")

Solve for c.

- math(rational functions application) -
**Reiny**, Thursday, October 22, 2009 at 6:37pmCreating a chart makes these kind of problems real easy

3 columns: Distance, Rate , Time and remember D = RT

2 rows: jet and cargo plane

-----D-----R------T

Jet 1400 -- x+100 -- 1400/(x+100)

Cargo 1400 ----x -- 1400/x

(hope the spacing comes out halfdecent.)

It said the time of the cargo plane is 25% more than the time of the jet, so

1400/x = 1.25(1400)/(x+100)

1400/x = 1750/(x+100)

cross-multiply

1750x = 1400x + 140000

x = 400

So the cargo's speed is 400 km/h and the jet goes 500 km/h

check:

time of jet = 1400/500 = 2.8 hours

time of cargo = 1400/400 = 3.5

What is 25% of 2.8 added to 2.8 ?

YUP!!!!

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