Posted by susie on Thursday, October 22, 2009 at 12:03pm.
Let the initial and final concentrations be Co and Ct.
To find k:
ln(Ct/Co)=-kt
ln(0.5) = -k(410s)
k = ____?
To find the concentration at (4)(410s), use the same equation:
ln(Ct/Co)=-kt
Use the value of k from the first part, and t = 4x410=1640s, then solve for for Ct.
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