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January 31, 2015

January 31, 2015

Posted by **Mathpleasehelp** on Thursday, October 22, 2009 at 2:59am.

- Math -
**Ajay Sir**, Thursday, October 22, 2009 at 6:46amKen buys 68 sweets.

- Math -
**Reiny**, Thursday, October 22, 2009 at 9:04ammake a chart:

....Jim...Ken

c choc's .. s sweets

after exchange:

(1/2)s + (1/2)c ... (1/2)s + (1/2)c

after eating:

Jim eats 12 sweets , so amount left:

(1/2)s - 12 sweets and (1/2)c choc's

but that ratio is 1:7

so [(1/2)s - 12]/[(1/2)c] = 1/7

(s - 24)/c = 1/7

c = 7s - 168 #1

Ken eats 18 choc's, so amount left"

(1/2)s + (1/2)s - 18

but that ratio is 1:4

so [(1/2)s]/[(1/2)c - 18] = 1/4

s/(c-36) = 1/4

4s = c-36

c = 4s - 36 #2

equate #1 and #2 and solve for s

7s-168 = 4s+36

s = 68

back in #1 I get

c = 308

check:

Jim : 68 sweets, Ken : 308 choc's

after exchange:

Jim has 34 sweets, 154 chocs

Ken has 34 sweets, 154 chocs, they have the same

after eating as stated above

Jim has 22 sweets, 154 chocs --> ratio = 22:154 = 1:7

Ken has 34 sweets, 136 choc's --> ratio = 34:136 = 1:4

checks!!!

- Math -
**Mathpleasehelp**, Friday, October 23, 2009 at 2:14amThanks so much Reiny and Ajay Sir

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