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April 1, 2015

April 1, 2015

Posted by **jason** on Wednesday, October 21, 2009 at 10:43pm.

blue, green, and yellow. If you draw two marbles from

the jar, one after another, replacing the first before

drawing the second, what is the probability of getting

a. two red marbles?

b. a red marble on the first draw and a green marble on

the second draw?

c. at least one red marble and one green marble?

d. no yellow marbles?

- math/probability -
**Reiny**, Wednesday, October 21, 2009 at 11:15pma) prob (red,red) = (1/4)(1/4) = 1/16

b) prob(red then green) = (1/4)(1/4) = 1/16

c) could be RG or GR

so prob = 1/16 + 1/16 = 1/8

(I don't see where the "at least" comes in, you are only drawing 2 and you want a red AND a green)

d) prob (no yellow, no yellow = (3/4)(3/4) = 9/16

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