Posted by **jason** on Wednesday, October 21, 2009 at 10:43pm.

A jar contains four marbles, each a different color: red,

blue, green, and yellow. If you draw two marbles from

the jar, one after another, replacing the first before

drawing the second, what is the probability of getting

a. two red marbles?

b. a red marble on the first draw and a green marble on

the second draw?

c. at least one red marble and one green marble?

d. no yellow marbles?

- math/probability -
**Reiny**, Wednesday, October 21, 2009 at 11:15pm
a) prob (red,red) = (1/4)(1/4) = 1/16

b) prob(red then green) = (1/4)(1/4) = 1/16

c) could be RG or GR

so prob = 1/16 + 1/16 = 1/8

(I don't see where the "at least" comes in, you are only drawing 2 and you want a red AND a green)

d) prob (no yellow, no yellow = (3/4)(3/4) = 9/16

## Answer This Question

## Related Questions

- Math - given a jar contains four marbles, each a different color: red, blue, ...
- Math - A jar contains four marbles, each a different color: red, blue, green, ...
- Math - given a jar contains four marbles, each a different color: red, blue, ...
- MATH Prob. - A jar contains four marbles, each a different color: red, blue, ...
- Math Probability question - A jar contains four marbles, each a different color...
- Math - given a jar contains four marbles, each a different color: red, blue, ...
- Statistics - 1.In a jar, suppose there are 3 blue marbles, 2 yellow marbles and ...
- Probabilities - A jar contains 2 red marbles, 3 green marbles, 4 blue marbles, ...
- Algebra - A jar contains red, blue and yellow marbles.The number of red marbles ...
- Algebra - Out of jar with 100 marbles, 49 are blue marbles, 7 are green marbles...

More Related Questions