If you add 1.0ml (cm3) of a aqueous solution of NaCl at 0.4mol to 9.0ml of water what's the final concentration of NaCl in mmol?

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To find the final concentration of NaCl in millimoles (mmol), we need to consider the initial concentration and volume of the aqueous solution and the final total volume.

1. Start by calculating the number of moles of NaCl in the initial solution:
Moles of NaCl = initial volume (in liters) x initial concentration (in moles/liter)

Given: initial volume = 1.0 mL = 0.001 L
initial concentration = 0.4 mol/L

Moles of NaCl = 0.001 L x 0.4 mol/L = 0.0004 mol

2. Determine the final volume of the solution by adding the initial aqueous solution to water:
Final volume = initial volume + volume of water

Given: initial volume = 1.0 mL = 1.0 cm3
volume of water = 9.0 mL = 9.0 cm3

Final volume = 1.0 cm3 + 9.0 cm3 = 10.0 cm3

3. Convert the final volume to liters:
Final volume (L) = Final volume (cm3) ÷ 1000

Final volume (L) = 10.0 cm3 ÷ 1000 = 0.01 L

4. Calculate the final concentration of NaCl in mmol:
Final concentration (mmol) = Moles of NaCl ÷ Final volume (L)

Final concentration (mmol) = 0.0004 mol ÷ 0.01 L = 0.04 mmol

Therefore, the final concentration of NaCl in the solution is 0.04 mmol.