Write the numeral in base ten.
7001eight.
Since a number to base eight has each digit value equal to powers of eight, you can multiply each digit by the appropriate power of eight.
For example,
12348
=4*80+3*1+2*82+1*83+
=4*1+3*8+2*64+1*512
= 66810
You can do the same for 70018 to get 358510.
7001 in base ten is:
1x(8^0)+0x(8^1)+0x(8^2)+7x(8^3)=1+7x512=1+3584=3585
Thank you both!
To write the numeral "7001eight" in base ten, we need to convert it from base eight (also known as octal) to base ten (decimal).
In the octal system, each digit represents a power of 8. The rightmost digit represents 8^0, the second-rightmost digit represents 8^1, the third-rightmost digit represents 8^2, and so on.
Let's break down the given number "7001eight" digit by digit:
The rightmost digit is 1, which represents 1 * 8^0 = 1 * 1 = 1.
The second-rightmost digit is 0, which represents 0 * 8^1 = 0 * 8 = 0.
The third-rightmost digit is 0, which represents 0 * 8^2 = 0 * 64 = 0.
The leftmost digit is 7, which represents 7 * 8^3 = 7 * 512 = 3584.
Now, we can add up these values to get the base ten equivalent of "7001eight":
1 + 0 + 0 + 3584 = 3585.
Therefore, "7001eight" in base ten is equal to 3585.