a man loses 12.5% of his money & after spending 70% of the remainder , he was left with Rs 210/- . the money he had at the beginning is?
Suppose he had Rs x at the start
After spending 12.5% or .125 of that he
has .875x left
He spends 70% of that, so he has
30% of the .875x
or .3(.875x) left
but .3(.875x) = 210
.2625x = 210
x = 210/.2625
= 800
8000
800
To find the amount of money the man had at the beginning, we'll follow these steps:
Step 1: Calculate the money after losing 12.5%
Let's assume the man's initial amount of money is 'x'.
After losing 12.5%, he will have (100% - 12.5%) = 87.5% of his initial amount.
So, the remaining amount after the first loss is 0.875x.
Step 2: Calculate the money after spending 70%
Now, the man spends 70% of the remaining amount.
The remaining amount after spending is (100% - 70%) = 30% of the previous amount.
So, the remaining amount after spending is 0.3 * 0.875x = 0.2625x.
Step 3: Calculate the remaining amount
Given that the man is left with Rs 210, we can set up the equation as follows:
0.2625x = 210
Step 4: Solve the equation
To find the value of 'x', we divide both sides of the equation by 0.2625:
x = 210 / 0.2625
By calculating the above equation, we find that the man originally had Rs 800. Therefore, the money he had at the beginning is Rs 800/-.