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December 20, 2014

December 20, 2014

Posted by **Emily** on Tuesday, October 20, 2009 at 8:09pm.

1. f(x) + 2

==> My graph I have is a line going through the points (-2,-1) and (2,2). Is this correct?

2. 2f(x)

==> Can someone help me with this one please? I thought the 2 in front of the f(x) would affect the amplitude of the graph, but I don't see how this graph would have an amplitude.

Any help is GREATLY appreciated!!!!!

- Math Analysis -
**jim**, Tuesday, October 20, 2009 at 8:38pmOK. The original function is

f(x)=(3/4)x-3/2

1. Yes, the function (3/4)x + 1/2 does pass through those points (-2,-1) and (2,2), as you can verify by plugging them in

2. You're right; there is no amplitude - but there is a slope! It doubles the slope, and the y-intercept.

2f(x) = 2(3/4)x-2(3/2)

=(3/2)x -3

That passes through (0,-3) and (-2,0)

- More help? :( -
**Emily**, Tuesday, October 20, 2009 at 9:19pmOhhhh I get it :) I have like two more questions though --

3. f(-2x)

==> Would you multiply the x- and y- coordinates by -2? I'm soooo confused :-/

And for number 8, the graph is a parabola instead, with the vertex at (0,0), and the "arms" of the parabola going through the points (-1,1), (1,1), and (2,4). A parabola doesn't have an amplitude either, so what exactly would you do here? (don't worry -- this isn't all my homework, these are just a few examples so I know how to do the others)

- Math Analysis -
**jim**, Tuesday, October 20, 2009 at 9:44pmYou don't multiply the co-ords, exactly. What you're scaling is the coefficients.

But careful: f(-2x) is not -2f(x)!

f(-2x) means might be a shorthand for f(g(x)), where g(x) = -2x.

-2f(x) would be

-2(3/4)x+2(3/2)

=3-(3/2)x

Your parabola is y=x^2, or

f(x) = x^2

so

2f(x) = 2x^2

and everything else, including the scaling, follows from that.

(-1,1) -> (-1,2)

(1,1) -> (1, 2)

(2, 4) -> (2, 8)

See? The y value is doubled, which is kind of obvious when you see that you're going from:

y = x^2

to

y = 2x^2

(And don't worry about being confused; that just means you're paying attention. :-)

- Math Analysis -
**Emily**, Tuesday, October 20, 2009 at 10:08pmOhhhh that makes PERFECT sense! :D I'm soo glad I get this now. Thanks so much!! :)

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