Posted by Georgia on Tuesday, October 20, 2009 at 4:38pm.
This and the other seem to be similar. Best to talk about the general method.
1. Find an expression for the distance between the two at time t.
In this case, with Pythagoras' help, that's
sqrt( (25t+30)^2 + (16t)^2)
= sqrt(881t^2 + 1500t + 900)
Nasty-looking thing. Call it
u = 881t^2 + 1500t + 900
and differentiate it.
du/dt = 1762t+1500
dy/du = 1/2sqrt(881t^2 + 1500t + 900)
so the whole thing is
(1762t+1500)/2sqrt(881t^2 + 1500t + 900)
Plug in t=7 and you're there.
=
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