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January 31, 2015

January 31, 2015

Posted by **Georgia** on Tuesday, October 20, 2009 at 4:38pm.

west at 25 knots and ship B is sailing north at 16 knots.

How fast (in knots) is the distance between the ships changing at 7 PM? (Note: 1 knot is a

speed of 1 nautical mile per hour.)

- calculus -
**jim**, Tuesday, October 20, 2009 at 5:37pmThis and the other seem to be similar. Best to talk about the general method.

1. Find an expression for the distance between the two at time t.

In this case, with Pythagoras' help, that's

sqrt( (25t+30)^2 + (16t)^2)

= sqrt(881t^2 + 1500t + 900)

Nasty-looking thing. Call it

u = 881t^2 + 1500t + 900

and differentiate it.

du/dt = 1762t+1500

dy/du = 1/2sqrt(881t^2 + 1500t + 900)

so the whole thing is

(1762t+1500)/2sqrt(881t^2 + 1500t + 900)

Plug in t=7 and you're there.

=

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