Thursday

November 27, 2014

November 27, 2014

Posted by **Julie** on Tuesday, October 20, 2009 at 8:58am.

Let triangle ABC be such that AB is not congruent to AC. Let D be the point of intersection of the bisector of angle A and the perpendicular bisector of side BC. Let E, F, and G be the feet of the perpendicular dropped from D to line AB, line AC, line BC.

Prove that:-

D lies outside the triangle on the circle through ABC.

- Geometry -
**Anonymous**, Tuesday, October 20, 2009 at 2:33pmCan some one please help me.

pleaseeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeee

**Answer this Question**

**Related Questions**

geometry - I need to figure out this proof, the figure is two triangles forming ...

geometry - I have triangle XYZ with BX as the bisector sides XY and XZ are ...

Trigonometry/Geometry - In most geometry courses, we learn that there's no such ...

Precalculus - In most geometry courses, we learn that there's no such thing as "...

geometry PLZ HELP!!!! - how do write and graph a coordinate proof? Isoceles ...

Geometry-PLEASE CHECK ANSWERS! - In isosceles triangle DEF, DE=DF. Which of the ...

Trigonometry/Geometry - Law of sines and cosines - In most geometry courses, we ...

Geometry.. - Given: A(3,-1), B(5,2), C(-2,0), P(-3,4), Q(-5,-3), R(-6,2). Prove...

Geometry - Given: A(3,-1), B(5,2), C(-2,0), P(-3,4), Q(-5,-3), R(-6,2). Prove: ...

another geometry question - BD is a perpendicular bisector of triangle ABC. XZ ...