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October 1, 2014

October 1, 2014

Posted by **6th grade** on Tuesday, October 20, 2009 at 2:46am.

- math -
**Bryan**, Tuesday, October 20, 2009 at 4:01amJim and Ken have the same number of sweets and chocolates to begin with, as each of them gave half to the other. So:

From Jim eating 12 sweets, we can conclude that S-12=7C, as the number of sweets he has after eating 12 is seven times the number of chocolates he has.

From Ken eating 18 chocolates, we can conclude that S=4(C-18) or S=4C-72.

We can substitute the equation from Ken into the Jim equation, getting 4C-72-12=7C. -84=3C. C=-28, so S=-192. Ken originally had 2S sweets, so Ken bought -384 sweets. Check to see if you have accurately written this problem down, as the answer seems suspect.

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