Saturday

December 20, 2014

December 20, 2014

Posted by **6th grade** on Tuesday, October 20, 2009 at 2:46am.

- math -
**Bryan**, Tuesday, October 20, 2009 at 4:01amJim and Ken have the same number of sweets and chocolates to begin with, as each of them gave half to the other. So:

From Jim eating 12 sweets, we can conclude that S-12=7C, as the number of sweets he has after eating 12 is seven times the number of chocolates he has.

From Ken eating 18 chocolates, we can conclude that S=4(C-18) or S=4C-72.

We can substitute the equation from Ken into the Jim equation, getting 4C-72-12=7C. -84=3C. C=-28, so S=-192. Ken originally had 2S sweets, so Ken bought -384 sweets. Check to see if you have accurately written this problem down, as the answer seems suspect.

**Answer this Question**

**Related Questions**

Math - Jim bought some chocolates and gave half of it to Ken.Ken bought sweets ...

math - Ken's average driving speed is 25km/hr faster than Jim's. In the same ...

MATH - The ratios of the number of sweets Abigail has to the number of sweets ...

math,(fraction) - Becky bought 25kg of sweets.she kept 1kg of sweets for her use...

Math - Jim ate 3/8 of pie and Jung ate 0.25 of the same pie. Shade the amounte ...

math - Jim ate 3/8 of a pie and jung ate 0.25 of the same pie. Shade the amount ...

math - Calvin and Ken bought a bag of 60 onions. They divide all of these onions...

MATH - Jim had 92 more marbles than Sam. After Sam gave Jim 18 marbles, Jim had ...

Math - Ken and Sam shared some marbles. The ratio of the number of marbles Ken ...

math - peter bought a bag of candy. He gave away ten percent of the candy too ...