Posted by Jane on Monday, October 19, 2009 at 11:16pm.
x"=-9.8
x'=INT (-9.8)=-9.8t+x'(0)
x= INT (-9.8t+x'(0))
= x'(0)*t-1/2 9.8t^2 + x(0)
b) given x(0)=100, x'(0)=0
x=-4.9t^2 if x=-100
then t= sqrt(100/4.9) when it hits the ground.
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