Tuesday

September 2, 2014

September 2, 2014

Posted by **Jane** on Monday, October 19, 2009 at 11:16pm.

(assuming no other forces) is

x" = -g, where x(t) is the height of the object

above the ground, t is time, and g is the gravitational constant. Find a general

expression to describe the height of the object above the ground with respect

to time, t; i.e. find x(t).

(b) Suppose the object is dropped from a height of 100 units (so x'(0) = 0 and

x(0) = 100), how long will it take to hit the ground?

- Physics -
**bobpursley**, Tuesday, October 20, 2009 at 6:04amx"=-9.8

x'=INT (-9.8)=-9.8t+x'(0)

x= INT (-9.8t+x'(0))

= x'(0)*t-1/2 9.8t^2 + x(0)

b) given x(0)=100, x'(0)=0

x=-4.9t^2 if x=-100

then t= sqrt(100/4.9) when it hits the ground.

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