Posted by Anonymous on Monday, October 19, 2009 at 10:46am.
well, centripetal force must be greater than weight
mg<=mv^2/r
v>=sqrt(g*r)
check that.
i don't know where to go from there
v is the minimum speed.
Consider the following equation in the y-direction.
Fy=T+Fg=ma
Or in this case...
T+Fg=(mv^2)/R
Tension equals to 0 because when the pail of water is at the highest point, tension is nonexistent.
Therefore...
mg=(mv^2)/R
Cancel out mass
g=(v^2)/R
(Rg)^(1/2)=v
Plug in values.
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