Posted by Gemini on Monday, October 19, 2009 at 6:29am.
ok, let's call your first result of
r = (a+8d) / (a+6d) #1 equation
You could also subtract the two equations to get
ar^2 - ar = 2d
r^2 - r = 2d/a let's call that #2
Here is where it gets messy...
sub #1 into #2
(a+8d)^2/(a+6d)^2 - (a+8d)/(a+6d) = 2d/a
finding a common denominator of (a+6d)^2 and simpifying the left side, I got
(2ad + 16d^2)/(a+6d)^2 = 2d/a
divide both sides by 2d
(a+8d)/(a+6d)^2 = 1/a
Cross-multiply and simplify to get
a^2 + 12ad + 3d^2 = a^2 + 8ad
36d^2 + 4ad = 0
9d^2 + ad = 0
d(9d + a) = 0
d = 0 (the arithmetic sequence would not change) OR
d = -9a
back into #1
r = (a+8d)/(a+6d)
= (-9d + 8d)/(-9d + 6d)
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