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March 3, 2015

March 3, 2015

Posted by **Bill** on Monday, October 19, 2009 at 2:47am.

- Physics -
**bobpursley**, Monday, October 19, 2009 at 7:19amThis is a rather silly problem.

You know horizontal velocity is constant

horizontal velocity=268Cos45

So the angle changes because of vertical velocity. The resultant angle, in the problem then is a tangent question

Vertical velocity=268Sin45-9.8 t

tanTheta=vertical/horizontal

you know tan for 17, and 45, so the idea is to figure time for each angle from this e quation

horizontavelocity*tanTheta=268Sin45-9.8 t

Once you have the two times, then distance=horzontal velocity (t1-t2)

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