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Algebra 2 URGENT

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  • Algebra 2 URGENT -

    here is my take:
    you know that x^-1 = 1/x

    so in the denominator you have
    (a^-1) - (b^-1) = 1/a - 1/b

    you need to have the same denominator, which you get by multiplying both in the numerator and denominatorby the other fraction's denominatior
    so you get:

    (b/ab)- (a/ab) = (b-a/ ab)

    the whole expression looks as this:

    (a-b)/[b-a/ab] <=> ab(a-b)/(b-a)

    multiplying inside the bracket you get:

    [(a^2)b - a(b^2)] / (b-a)

    hope this helps...otherwise some other genious may help u :-D ..goodluck.

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