Posted by Trisan on Monday, October 19, 2009 at 12:23am.
here is my take:
you know that x^-1 = 1/x
so in the denominator you have
(a^-1) - (b^-1) = 1/a - 1/b
you need to have the same denominator, which you get by multiplying both in the numerator and denominatorby the other fraction's denominatior
so you get:
(b/ab)- (a/ab) = (b-a/ ab)
the whole expression looks as this:
(a-b)/[b-a/ab] <=> ab(a-b)/(b-a)
multiplying inside the bracket you get:
[(a^2)b - a(b^2)] / (b-a)
hope this helps...otherwise some other genious may help u :-D ..goodluck.
Related Questions
Algebra 2 URGENT - Simplify: 1/y^2-y-2+1/y^2+y
Algebra 2 URGENT - Simplify: (1)/(t^2+t)+(1)/(t^2-t)
Algebra 2 URGENT - Simplify: (x)/(x-1)-(1)/(x+1)
Algebra 2 URGENT - Simplify: (1)/(z-4)-(1)/z+4
Algebra 2 URGENT - Simplify: x+2/x^2+x-2/2x
Algebra 2 URGENT - Simplify: 1/u^2-2u-1/u^2-4
Algebra 2 URGENT - Simplify: (1)/u^2-(2u)/(1)/(u^2-4)
ALGEBRA 2 URGENT! PLEASE HELP! - Simplify 8(2^x-1)=64
Algebra 2 URGENT - Simplify: 4s^-2-(4t)^-2
Algebra 2 URGENT - Simplify: 4s^-2-(4t)^-2
For Further Reading
