Friday

December 19, 2014

December 19, 2014

Posted by **Trisan** on Monday, October 19, 2009 at 12:23am.

(a-b)/(a^-1-b^-1)

- Algebra 2 URGENT -
**Gemini**, Monday, October 19, 2009 at 7:17amhere is my take:

you know that x^-1 = 1/x

so in the denominator you have

(a^-1) - (b^-1) = 1/a - 1/b

you need to have the same denominator, which you get by multiplying both in the numerator and denominatorby the other fraction's denominatior

so you get:

(b/ab)- (a/ab) = (b-a/ ab)

the whole expression looks as this:

(a-b)/[b-a/ab] <=> ab(a-b)/(b-a)

multiplying inside the bracket you get:

[(a^2)b - a(b^2)] / (b-a)

hope this helps...otherwise some other genious may help u :-D ..goodluck.

**Answer this Question**

**Related Questions**

Algebra 2 URGENT - Simplify: x+2/x^2+x-2/2x

Algebra 2 URGENT - Simplify: 1/u^2-2u-1/u^2-4

Algebra 2 URGENT - Simplify: 4s^-2-(4t)^-2

Algebra 2 URGENT - Simplify: 1/y^2-y-2+1/y^2+y

Algebra 2 URGENT - Simplify: (1)/(t^2+t)+(1)/(t^2-t)

Algebra 2 URGENT - Simplify: (1)/u^2-(2u)/(1)/(u^2-4)

Algebra 2 URGENT - Simplify: (x)/(x-1)-(1)/(x+1)

Algebra 2 URGENT - Simplify: (1)/(z-4)-(1)/z+4

Algebra 2 URGENT - Simplify: 4s^-2-(4t)^-2

ALGEBRA 2 URGENT! PLEASE HELP! - Simplify 8(2^x-1)=64