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Fourteen people attend a meeting. If each person shook hands with every other person, how many handshakes were there altogether?

  • maths -

    In combination notation, that would be
    C(14,2) = 14!/(12!2!) or 91


    Each of the 14 people can shake hands with 13 other people, that would be 14x13 = 182 handshakes.
    But that would be all cases of A shaking with B and B shaking with A, that is, we care counting each handshake twice.
    So divide the 182 by 2 to get 91

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