Saturday

April 19, 2014

April 19, 2014

Posted by **Trisan** on Sunday, October 18, 2009 at 10:46pm.

- Algebra 2 URGENT -
**Amber**, Sunday, October 18, 2009 at 10:53pmI can't tell you how to set it up but I can tell you that she invested $3000 at 9% and $1500 at 6%.

3000 x .09 = 270

1500 x .06 = 90

270 - 90 = 180

- Algebra 2 URGENT -
**Reiny**, Sunday, October 18, 2009 at 11:28pmlet the amount invested at 9% be x

then the amount invested at 6% is 4500-x

.09x + .06(4500-x) = 180

solve for x

**Related Questions**

Algebra 2 - Sally invested a total of $4500, some at 9% per year and the rest at...

Algebra @ - Sally invested a total of $4500, some at 9% per year and the rest at...

investment - A certain amount of money is invested at 6% per year. A second ...

investment - A certain amount of money is invested at 6% per year. A second ...

algebra - Last year, Susan had 30,000 to invest. She invested some of it in an ...

business - A women has $500,000 invested in two rental properties. One yields an...

Algebra 1 honors - Mr. Oliver invested a total of $6400, part at 9% per year and...

Math 0098 - Last year, Deon had $20,000 to invest. He invested some of it in an...

Math - The management of a private investment club has a fund of $114,000 ...

Math 0098 - Last year, Joe had to invest. He invested some of it in an account ...