Posted by David. on .
The Temperature T of food put in a freezer is
T = (700) / t^2+4t+10
where t is the time in hours. Find the rate of change of T with respect to t at each of the following times.
a. t=1
b. t=3
c. t=5
d. t=10
** i'll be able to do the others on my own if you please explain step by step how to do at least one of these. I have now idea where to start. SOMEONE PLEASE HELP ME A.S.A.P ! :(
THANK YOU.

AP Calculus  High School 
Vipster,
you gotto differentiate the function
so if
T= 700* (t^2) + 4t + 10
dT/dt = 700* (2) (t^ 3) +4
now just plug in t = 1 in the above
same with the others too