 |
|
|
|
|
SCHOOL SUBJECTS
-
-
-
-
-
-
-
-
-
-
-
-
|
|
|
|
GRADE LEVELS
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
-
|
|
|
|
|
|
Post a New Question | Current Questions | Chat With Live Tutors
Posted by David. on Sunday, October 18, 2009 at 9:36pm.
The Temperature T of food put in a freezer is
T = (700) / t^2+4t+10
where t is the time in hours. Find the rate of change of T with respect to t at each of the following times.
a. t=1
b. t=3
c. t=5
d. t=10
** i'll be able to do the others on my own if you please explain step by step how to do at least one of these. I have now idea where to start. SOMEONE PLEASE HELP ME A.S.A.P ! :(
THANK YOU.
|
- AP Calculus - High School - Vipster, Sunday, October 18, 2009 at 9:43pm
you gotto differentiate the function
so if
T= 700* (t^-2) + 4t + 10
dT/dt = 700* (-2) (t^ -3) +4
now just plug in t = 1 in the above
same with the others too
|
Answer this Question
|
|
|
|
