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calculus

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how do not understand how to find a deriviative of this function?Do i use chain rule and product rule?

r= the square root of (theta*sin*theta)


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  • calculus - ,

    ok, if f(u) exists, and u=G(x)
    then

    y= f(u)
    dy/dx= d(f(u)/du * du/dx

    but u=G(x)
    so du/dx= G'

    Now in practice.
    r= sqrt(Theta*sinTheta)

    dr/dtheta= 1/2 (1/sqrt(Theta*sinTheta))* d(theta*sinTheta)/dtheta
    and d(theta*sinTheta)/dtheta= sinTheta+ theta*cosTheta.

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